A) Y=0.12x and the Y value is dependent whole X value is independent
b) Just make a table and multiple each value by the equation
c) The domain would be the lowest and highest values of X and the range would be the lowest and highest values of Y (double check me on this to be sure)
d) A day = (0.12)(300)+(0.12)(750)+(0.12)(1050)
A week = (0.12)(300)+(0.12)(750)+(0.12)(1050) and multiply that by 7
The given equation is:
ax2 + bx + c = 0
We have the resolvent is:
x = (- b +/- root (b2 - 4ac)) / (2a)
The discriminant is:
b2 - 4ac = 0
The solution will be:
x = (- b) / (2a)
Thus, the equation has a real solution.
Answer:
option B
Can you post original picture of question please
5/8 * 125/125 = 625/1,000 = 0.625
62.5 percent
Solution: 62.5%
2y^3 – 2y – 10y + 10 + y^2 – 1 < 0 [the terms are simply reorganized again]
factor 2y from the first two terms, -10 from the second two terms
2y (y^2 -1) – 10 (y-1) + y^2 – 1 < 0
2y (y+1)(y–1) – 10 (y-1) + (y+1)(y–1) < 0 [ because y^2 – 1 = (y+1)(y–1) ]
factor out (y-1) from all the terms
(y-1) [2y(y+1)-10+ y+1] < 0
(y-1) [(y+1) (2y+1) - 10] < 0
Let us simplify (y+1) (2y+1) - 10 < 0 now
(y-1) (2y^2+y+2y+1-10) < 0
(y-1) (2y^2 +3y -9 < 0
(y-1) (2y^2 +6y -3y - 9) < 0 [ because 3y = 6y -3y] j