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3 years ago

Graph the linear function. f(x)=x+2 HELP PLEASE

Mathematics

1 answer:

Serggg [28]3 years ago

7 0

Hey there!

Graphing this will be similar to graphing slope intercept equations (y=mx+b).

As you can see, we have a slope of 1 and a y-intercept of two when you look at the equation and match it up with the slope intercept form Let's look at each answer option and see which one fits.

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GRAPH A

Graph A does have a y-intercept of two. This means that the line crosses the y-axis at two units up from the origin. However, it has a negative slope because it is going downwards rather than upwards. The slope of our function is positive, so Graph A does not match.

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GRAPH B

Graph B does have a positive slope of one (a slope of one means that it goes diagonally across every small square on the grid), but it's y-intercept is -2 because it hits the y-axis at 2 down from the origin. Therefore, Graph B does not match this function.

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GRAPH C

Graph C both goes downward (negative slope) and it hits the y-axis at -2 instead of 2 (wrong y-intercept). Therefore, Graph C does not match the function.

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GRAPH D

Graph D has a y-intercept of 2 and it has a positive slope of one! Therefore, Graph D does match this function.

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The correct answer is Graph D.

I hope that this helps! Have a wonderful day!

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$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

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