Answer:
9√3- ^5√9
you would need to write in exponential form
Answer:
Sean's rocket lands 3 seconds after Kiara's rocket.
Step-by-step explanation:
Kiara: f(t)= -16t² + 80t
Sean: h(t) = -16t² + 120t + 64
Assume that both rockets launch at the same time. We need to be suspicious of Sean's rocket launch. His equation for height has "+64" at the end, whereas Kiara's has no such term. The +64 is the starting height iof Sean's rocket. So Kiara has a 64 foot disadvantage from the start. But if it is a race to the ground, then the 64 feet may be a disadvantage. [Turn the rocket upside down, in that case. :) ]
We want the time, t, at which f(t) and h(t) are both equal to 0 (ground). So we can set both equation to 0 and calculate t:
Kiara: f(t)= -16t² + 80t
0 = -16t² + 80t
Use the quadratic equation or solve by factoring. I'll factor:
0 = -16t(t - 5)
T can either be 0 or 5
We'll choose 5. Kiara's rocket lands in 5 seconds.
Sean: h(t) = -16t² + 120t + 64
0= -16t² + 120t + 64
We can also factor this equation (or solve with the quadratic equation):
0 = -8(t-8)(2t+1)
T can be 8 or -(1/2) seconds. We'll use 8 seconds. Sean's rocket lands in 8 seconds.
Sean's rocket lands 3 seconds after Kiara's rocket.
Ik its messy but i hope this helps:]
Answer:
Step-by-step explanation:
Triangle IJK is a right angle triangle.
From the given right angle triangle
JK represents the hypotenuse of the right angle triangle.
With ∠K as the reference angle,
IK represents the adjacent side of the right angle triangle.
IJ represents the opposite side of the right angle triangle.
To determine Cos K, we would apply trigonometric ratio
Cos θ = adjacent side/hypotenuse. Therefore,
Cos K = 36/85
Cos K = 0.4235
Rounding up to the nearest hundredth,
Cos K = 0.42
Answer:
1161 ft
Step-by-step explanation:
36 ft with the triangles, 900 ft with the squares, 225 ft for the bottom square, so total is 1161 ft.
