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Romashka [77]
3 years ago
6

Think your a pro at riddles?

Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

nine

Step-by-step explanation:

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How do solve this problem? <br> 1 2/5x =7
elena55 [62]

Answer:

if you are solving for x then the answer is 5

Step-by-step explanation:

5 0
3 years ago
Caleb bought groceries and paid
lutik1710 [3]

Answer:

Price of Caleb's groceries before tax= $6.4

Step-by-step explanation:

Let price of groceries before tax be = $ x

Sales tax % = 2.5%

Sales tax applied = 2.5\% \ of\ x = \frac{25}{100}\times x = \frac{25}{100} x

Actual sales tax paid = $1.60

∴ \frac{25}{100}x=1.60

Multiplying both sides by 100.

100\times \frac{25}{100}x=1.60\times 100

25x=160

Dividing both sides by 25.

\frac{25x}{25}=\frac{160}{25}

x=6.4

∴ Price of groceries before tax= $6.4

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3 years ago
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Which algebraic expression could NOT represent the phrase below?
skad [1K]

Answer:

B

Step-by-step explanation:

because 4 and 3 are grouped together you would add them first. this would change the outcome of the problem.

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3 years ago
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Which polynomial is prime​
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We need more information. You don't give us enough information....? Provide an image please. Or at least name the polynomials...

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The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
2 years ago
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