There are two equation of the system
(1) The perimeter
2(w + l) = p
2(w + l) = 86
(2) The length and the width
2w = l + 2
From the second equation
l + 2 = 2w
l = 2w - 2
Subtitute l with 2w - 2 in the first equation to find the width
2(w + 2w - 2) = 86
2(3w - 2) = 86
6w - 4 = 86
6w = 90
w = 15
Now, find the length by subtituting w with 15
l = 2(15) - 2
l = 30 - 2
l = 28
The dimension of the rectangle
length = 28 cm
width = 15 cm
Break the two denominators down to their primes.
9: 3 * 3
12:2 * 2 * 3
LCD: 2*2*3*3
LCD: 4 * 9
LCD:36
