The perimeter of a rectangle is 86. The length of the rectangle is one more than twice the width. Determine the length and width
of the rectangle.
1 answer:
There are two equation of the system
(1) The perimeter
2(w + l) = p
2(w + l) = 86
(2) The length and the width
2w = l + 2
From the second equation
2w = l + 2
l + 2 = 2w
l = 2w - 2
Subtitute l with 2w - 2 in the first equation to find the width
2(w + l) = 86
2(w + 2w - 2) = 86
2(3w - 2) = 86
6w - 4 = 86
6w = 90
w = 15
Now, find the length by subtituting w with 15
l = 2w - 2
l = 2(15) - 2
l = 30 - 2
l = 28
The dimension of the rectangle
length = 28 cm
width = 15 cm
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Step-by-step explanation:
How are we supposed to answer theres no table
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