Answer:
Step-by-step explanation:
since AD is a median it implies that triangle ABC is bisected to two equal right angled triangle which are ADB and ADC.
FE is parrallel to BC and cuts AB at F and AC at E shows that there are two similar triangles formed which are AFE and ABC.
Recall that ADC is a right angled triangle, ED bisects a right angled triangle the the ADE = 
.
Now, Let FD bisect angle ADB,
then ADF = too.
Since AFX is similar to Triangle ABD and that Triangle AEX is similar to Triangle ACD, then EDX is similar to FDX
FDE = ADF + ADE = 
Answer:
c=
ad+b
a
give me brilliant please
Step-by-step explanation:
a=
b
c−d
Step 1: Multiply both sides by c-d.
ac−ad=b
Step 2: Add ad to both sides.
ac−ad+ad=b+ad
ac=ad+b
Step 3: Divide both sides by a.
ac
a
=
ad+b
a
c=
ad+b
a
Answer: f(a-2) = 2a² - 14a + 28
Step-by-step explanation:
f(x) = 2x² - 6x + 8
you can take a-2 and substitute it for each x, which would look like this:
f(a-2) = 2(a-2)² - 6(a-2) + 8
then distribute those in ( )
f(a-2) = 2a² - 8a + 8 - 6a + 12 + 8
combine like terms
f(a-2) = 2a² - 14a + 28
Answer:
Daniel's Mistake was that she didnt add all the sides
Step-by-step explanation:
She only added the right side of the triangle, and the right and bottom sides of the square. She is missing the left of the triangle, which is another 6x-4, and the left side of the square, which is 12x +3.
Using these sides the answer should look like this,
set up your problem
1) (6x-4)*2 + (12x+3)*2 + (14x+13)
multiply your 2's in
2) (12x-8) + (24x+6) + (14x+13)
simplify
3) 50x + 11 is your answer
