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Natali [406]
3 years ago
10

Solve for x in the equation x squared + 14 x + 17 = negative 96. x = negative 7 plus-or-minus 4 StartRoot 6 EndRoot i x = –7 ± 8

i x = 7 plus-or-minus 4 StartRoot 6 EndRoot i x = 7 ± 8i
Mathematics
2 answers:
blagie [28]3 years ago
7 0

Answer:

x=-7\pm8i

Step-by-step explanation:

we have

x^{2} +14x+17=-96

Equate to zero

x^{2} +14x+17+96=0

x^{2} +14x+113=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} +14x+113=0

so

a=1\\b=14\\c=113

substitute in the formula

x=\frac{-14\pm\sqrt{14^{2}-4(1)(113)}} {2(1)}

x=\frac{-14\pm\sqrt{-256}} {2}

Remember that

i=\sqrt{-1}

so

x=\frac{-14\pm16i} {2}

x=-7\pm8i

Slav-nsk [51]3 years ago
3 0

Answer:

its b on edge

Step-by-step explanation:

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3 years ago
What value of n makes the equation true?
dybincka [34]

1(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20                        i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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1 year ago
How do you find DE, Round to nearest 10th
Sergeu [11.5K]

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Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

cos\alpha=\frac{adjacent}{hypotenuse}

From the figure you can identify that:

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Then, you can substitute values:

cos(53\°)=\frac{DE}{10}

The next step is to solve for DE in order to find its value. This is:

10*cos(53\°)=DE\\\\DE=6.01

Finally, rounding the result to the nearest tenth, you get that this is:

DE\approx6.0

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3 years ago
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