Answer:
$46.42
Step-by-step explanation:
a=price after discount (without sales tax)
a/55=20/100
100a=55·20
100a/100=1,100/100 (the 1,100 is from the 55·20)
You get 11 and then you have to subtract 11 from 55.
55-11=44, so a=44
Then you multiply 44·0.055 (you get 0.055 because you have to make 5.5% a decimal. You get 2.42.
You add 2.42 and 44 and you get $46.42
9514 1404 393
Answer:
x = 0
Step-by-step explanation:
You can eliminate parentheses and subtract 50.
5(2x +10) = 50
10x +50 = 50 . . . . use the distributive property
10x = 0 . . . . . . . . . subtract 50 from both sides
x = 0 . . . . . . . . . . . divide by 10
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<em>Check</em>
5(2·0 +10) = 50
5(10) = 50 . . . . true
Answer:
x∈[20/3;+∝).
Step-by-step explanation:
3x+10≥30; ⇔ 3x≥20; ⇔ x≥20/3
Answer:
His estimate is not correct
Each employee gets 205.6875
Step-by-step explanation:
Bonus to give out = 6582
Number of employees to get bonus = 32
Bonus per employee = Total bonus / number of employees
= 6582 / 32
= 205.6875
Each employee will get 205.6875 contrary to manger Jake reasoning of 2000 per employee
manger Jake reasoning
6572 / 32
32 in 65 = 2 remainder 1
He added 000 zeros to 2 which is wrong
He should have added 00 zeros to 2 because he has 172 remaining after dividing 65 by 32
Answer:
(3,1) and (3,2)
Step-by-step explanation:
We are given that a relation
{(0,0.5),(0.5,1),(3,1),(1,6),(3,2)}
We have to find that ordered pair which causes this relation not to be a function.
We know that
Function: It is a mapping between two non- empty set A and B.
Every element of set A has unique image in set B.
One element of set A can not have two or more images in set B.
Two or more elements of set A have same images in set B.
In given relation images of 3 are 1 and 2 which is not possible if a relation is function because one element can not have two or more images.
The ordered pair (3,2) and (3,1) cause this relation not to be a function because image of 3 are 1 and 2 which is not possible .
Answer: (3,1) and (3,2)
