Answer:
1/5 or 0.2 i hope this helped you
Answer:
please give me brainlest
Step-by-step explanation:
16 is the answers for the question
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
(2, 0)
Step-by-step explanation:
Given the simultaneous equation
2x-y = 4
3x+y = 6
Add both equation
2x+3x = 4 + 6
5x = 10
x = 10/5
x = 2
Substitute x = 2 into equation 1
From1 ;
2x-y = 4
2(2) - y = 4
4 - y = 4
y = 4-4
y = 0
Hence the solution to the system of equation is (2, 0)
