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Scorpion4ik [409]
3 years ago
5

How to solve this problem

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:i fffffffffffffffffffffoooooooooooooooooooooorrrrrrrrrrrrrrrrrrggggggggggggggggggggggooooooooooooooooooottttttttttttttttttttttttttt


Step-by-step explanation:


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A binomial probability distribution has p = .20 and n = 100.
AleksAgata [21]

Answer:

Mean = 0.2(100) = 20

Variance = 0.2×0.8×100 = 16

Standard deviation = 4

Yes, np > 5 & nq > 5

3 0
3 years ago
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Factor the following :
TEA [102]

Answer:

(6x - 7y)(6x + 7y)

Step-by-step explanation:

36x² - 49y² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

36x² - 49y²

= (6x)² - (7y)²

= (6x - 7y)(6x + 7y)

4 0
3 years ago
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Can you please help with this
sleet_krkn [62]

Answer:

Exercise 1 : a. 4 ; b. -4

Exercise 2 : a. +7 positive/right ; b. -7 ; c. -7 negative/left

Step-by-step explanation:

8 0
3 years ago
20 large plastic bottles can be recycled to make 1 fleece jacket.
Kryger [21]
14 fleece jackets can be made
5 0
3 years ago
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For 0 ≤ θ < 2 π what are the solutions to sin^2(θ) =2sin^2(θ/2)
gregori [183]

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0   or   1 - cos(θ) = 0

cos(θ) = 0   or   cos(θ) = 1

[θ = arccos(0) + 2nπ   or   θ = -arccos(0) + 2nπ]

…   or   [θ = arccos(1) + 2nπ   or   θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ   or   θ = -π/2 + 2nπ]   or   [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0   ⇒   θ = π/2

• second solution set with n = 1   ⇒   θ = 3π/2

• third solution set with n = 0   ⇒   θ = 0

So, the first choice is correct.

6 0
2 years ago
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