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3 years ago

Select the correct answer.

Mathematics

2 answers:

jenyasd209 [6]3 years ago

6 0

I think the correct answer is b

Rainbow [258]3 years ago

5 0

I think it’s b leetttttt ggggggooo

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Solve each equation. Show all steps and work. your answers to four decimal places.

Virty [35]

Answer:

This equation is incorrect. The equation simplifies to -3=4 which is incorrect.

Step-by-step explanation:

3(-3)=-9. 3(2)=6

-9+6=-3

-3=4 FALSE

5 0

3 years ago

Select the story problem that this equation represents 1/2 / 2/5

grin007 [14]

Answer:

d is your answer

Step-by-step explanation:

8 0

3 years ago

The ages of a random sample of five university professors are 39, 54, 61, 72, and 59. Using this information, find a 99% confide

kondor19780726 [428]

Answer:

99% confidence interval for the population standard deviation = (74.97 , 635.20).

Step-by-step explanation:

We are given that the ages of a random sample of five university professors are 39, 54, 61, 72 and 59. Also, it is provided that the ages of university professors are normally distributed.

So, firstly the pivotal quantity for 99% confidence interval for the population standard deviation is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation

$\sigma$ = population standard deviation

n = sample of university professors = 5

Also, $s^{2}$ = $\frac{\sum (X-\bar X)^{2} }{n-1}$ = 144.5

So, 99% confidence interval for population standard deviation, $\sigma$ is;

P(0.2070 < $\chi^{2} __5_-_1$ < 14.86) = 0.99 {As the table of $\chi^{2}$ at 4 degree of freedom

gives critical values of 0.2070 & 14.86}

P(0.2070 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 14.86) = 0.99

P( $\frac{ 0.2070}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{ 14.86}{(n-1)s^{2} }$ ) = 0.99

P( $\frac{ (n-1)s^{2}}{14.86 }$ < $\sigma^{2}$ < $\frac{ (n-1)s^{2}}{0.2070 }$ ) = 0.99

99% confidence interval for $\sigma^{2}$ = ( $\frac{ (n-1)s^{2}}{14.86 }$ , $\frac{ (n-1)s^{2}}{0.2070 }$ )

= ( $\frac{ (5-1) \times 144.5^{2}}{14.86 }$ , $\frac{ (5-1) \times 144.5^{2}}{0.2070 }$ )

= (5620.525 , 403483.092)

99% confidence interval for $\sigma$ = ( $\sqrt{5620.525}$ , $\sqrt{403483.092}$ )

= (74.97 , 635.20)

Therefore, 99% confidence interval for the population standard deviation of the ages of all professors at the university is (74.97 , 635.20).

8 0

4 years ago

Anya says, "62,996 rounds to 63,000"

Diano4ka-milaya [45]

Answer:

hundreds

Step-by-step explanation:

hundreds because in the hundreds place in the number 62996 there's number 9, which it's greater than 4, so it will add 1 to the thousands and all the numbers in the right will be zero

3 0

4 years ago

Find the

Umnica [9.8K]

Answer:

1. 135 2. 16.875

Step-by-step explanation:

1. 5 x 4.5 x 6 = 135

2. 2.5 x 2.25 x 3 = 16.875

8 0

3 years ago