The local Red Cross had a goal of people donating 1000 pints of blood. Each person can usually give 1 pint. What percent of the
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A washer has outer radius 
and inner radius 
![\displaystyle V = \int_0^1 \pi\Big[ \left( 2 - x^2 \right)^2 - \left( 2 - \sqrt{x}\right)^2\Big] dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V%20%3D%20%5Cint_0%5E1%20%5Cpi%5CBig%5B%20%5Cleft%28%202%20-%20x%5E2%20%5Cright%29%5E2%20-%20%5Cleft%28%202%20-%20%5Csqrt%7Bx%7D%5Cright%29%5E2%5CBig%5D%20dx)
The value is 333
<h3>How to determine the function</h3>From the information given, we have:
- x = - 8
- 1/3*h(x) = x^2-5x+7
Now, let's substitute the value of 'x' in the function:
1/3*h(x) = x^2-5x+7
1/ 3 × h(-8) = ( - 8)² - 5 ( -8) + 7
Make 'h ( -8)' the subject of formula
h ( -8) =
h ( -8) =
Take the sum of the numerator
h ( -8) =
Take the inverse of the denominator and multiply
h ( -8) = 111 × 3/ 1
h ( -8) = 333
We can see that through the substitute of the value of x as - 8, we get 333
Thus, the value is 333
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a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,
6! = 6 5
= 30 4
= 360 2 = 720 possible ways to order 6 people in a row
b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.
5! = 5 4
= 20 3
= 120 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.
In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )
c. With each husband on the left, there are 3 people left, all women, that we have to consider here.
3! = 3 2 6 ways to arrange 3 couples in a row, the husband always to the left