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Sloan [31]
3 years ago
6

What is the value for AG at 300 K if AH = 27 kJ/mol and AS = 0.09 kJ/(mol:K)? HURRY!

Chemistry
1 answer:
Lilit [14]3 years ago
7 0

Answer:0

Explanation:

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HELP! ASAP!!! WILL MARK BRAINLIEST!!
san4es73 [151]

Answer:

Rb

Alkali Metals are Group 1 so

Rb it isnt Hydrogen because it is a gas

Explanation:

8 0
3 years ago
Read 2 more answers
True or false a contour line indicates that all points on that line have equal elevation
Helga [31]
True. Each contour line on a topographic map represent a certain elevation; the closer they are, the steeper the surface is. All points on a contour line are the same elevation.
3 0
3 years ago
1. How many molecules of S2 gas are in 756.2 L?
AfilCa [17]

Answer: There are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

Explanation:

It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of  moles present in 756.2 L are calculated as follows.

Mole = \frac{Volume}{22.4 L}\\= \frac{756.2 L}{22.4 L}\\= 33.76 mol

According to mole concept, 1 mole of every substance contains 6.022 \times 10^{23} molecules.

Therefore, molecules of S present in 33.76 moles are calculated as follows.

1 mol = 6.022 \times 10^{23}\\33.76 mol = 33.76 \times 6.022 \times 10^{23}\\= 2.032 \times 10^{25}

Thus, we can conclude that there are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

5 0
3 years ago
If you refuse a legal chemical test issued by a law enforcement officer, the Division of Motor Vehicles is required to:
Andru [333]

Answer: Revoke the driver's license for at least 12 months

Explanation:

Chemical tests are used in order to measure the amount of drugs or alcohol that is in the body of a person when the person was arrested. To do this, samples of the urine or blood of the person can be taken and the result will be used to know if the person was driving under the influence of alcohol or not.

If the person refuse a legal chemical test issued by a law enforcement officer, the Division of Motor Vehicles is required to revoke the the driver's license of the person for at least 12 months.

6 0
2 years ago
At a certain temperature, 0.900 mol of SO3 is placed in a 2.00-L container.
Goryan [66]

Answer:

Kc = 2.34 mol*L

Explanation:

The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.

A + B ⇄ C + D

Kc = [C] * [D] / [A] * [B]

According to the reaction

Kc = [SO2]^2 * [O2]^2 / [SO3]^2

Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3

0.450 --> 0 + 0 (Beginning of the reaction)

0.260 --> 0.260 + 0.130 (During the reaction)

0.190 --> 0.260 + 0.130 (Equilibrium of the reaction)

Kc = [0.260]^2 + [0.130]^2 / [0.190]^2

Kc = 2.34 mol*L

3 0
3 years ago
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