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Vsevolod [243]
3 years ago
11

How much heat is produced by combustion of 125 g of methanol under standard state conditions?

Chemistry
2 answers:
Sonbull [250]3 years ago
8 0

Answer:

Energy released = 2832.79 kJ

Explanation:

The standard enthalpy of the combustion of methanol, \Delta\ H^0=-726.1\ kJ/mol

It means that :

1 mole of methanol on combustion releases 726.1 kJ of energy

Molar mass of methanol = 32.04 g/mol

Thus, mass of 1 mole of methanol is 32.04 g

So,

32.04 g of methanol on combustion releases 726.1 kJ of energy

1 g of methanol on combustion releases 726.1/32.04 kJ of energy

125 g of methanol on combustion releases (726.1/32.04)*125 kJ of energy

<u>Energy released = 2832.79 kJ</u>

Alex777 [14]3 years ago
4 0
Standard enthalpy of combustion is the enthalpy change for one mole of a substance that burns or combines with the oxygen under the standard state conditions that is 1 bar pressure and  temperature. 
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