If an anhydrous Cupric Perchlorate weighs 262.447g/mol initially and weighs 370.540 g/mol after sitting on the bench to absorb water from the air, the number of water molecules absorbed would be 6 moles.
First, let us calculate the amount of water gained during the course of staying on the bench:
Water gained = weight after gaining water - initial weight
= 370.540 - 262.447
= 108.093g/mole
The total amount of water gained per mol is 108.093. Each water molecule weighs 18.015 g/mole. Thus, the total number of water molecules that will sum up to 108.093 would be:
108.093/18.015 = 6 moles
In other words, the number of water molecules absorbed by the Cupric Perchlorate is 6 moles.
More on calculating water of hydration can be found here: brainly.com/question/919417
CO₂, will have the lowest boiling point among the following ,therefore option (d) is correct.
<h3>What do you mean by the boiling point?</h3>
The temperature at which liquid vapor pressure equals atmospheric pressure is referred to as boiling point.
The boiling point is defined as the temperature at which a liquid’s saturated vapor pressure equals the atmospheric pressure surrounding it.
The boiling point for any material is the temperature point at which the material transforms into its form.
The one with the lowest boiling point has the weakest intermolecular forces.
CO₂, will have the lowest boiling point among the following ,therefore option (d) is correct.
Learn more about boiling point, here:
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We need more information to answer this.
<h3>
Answer:</h3>
56.11 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Compound] KOH
<u>Step 2: Identify</u>
[PT] Molar Mass of K - 39.10 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
<u>Step 3: Find</u>
39.10 + 16.00 + 1.01 = 56.11 g/mol
