Leftover: approximately 11.73 g of sulfuric acid.
<h3>Explanation</h3>
Which reactant is <em>in excess</em>?
The theoretical yield of water from Al(OH)₃ is lower than that from H₂SO₄. As a result,
- Al(OH)₃ is the limiting reactant.
- H₂SO₄ is in excess.
How many <em>moles</em> of H₂SO₄ is consumed?
Balanced equation:
2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O
Each mole of Al(OH)₃ corresponds to 3/2 moles of H₂SO4. The formula mass of Al(OH)₃ is 78.003 g/mol. There are 15 / 78.003 = 0.19230 moles of Al(OH)₃ in the five grams of Al(OH)₃ available. Al(OH)₃ is in excess, meaning that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.
How many <em>grams</em> of H₂SO₄ is consumed?
The molar mass of H₂SO₄ is 98.076 g.mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.076 = 28.289 g.
How many <em>grams</em> of H₂SO₄ is in excess?
40 grams of sulfuric acid H₂SO₄ is available. 28.289 grams is consumed. The remaining 40 - 28.289 = 11.711 g is in excess. That's closest to the first option: 11.73 g of sulfuric acid.
Answer:
V = 22.34 L
Explanation:
Given data:
Volume of O₂ needed = ?
Temperature and pressure = standard
Number of molecules of water produced = 6.0× 10²³
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of water:
1 mole contain 6.022× 10²³ molecules
6.0× 10²³ molecules × 1 mole / 6.022× 10²³ molecules
0.99 mole
Now we will compare the moles of oxygen and water.
H₂O : O₂
2 : 1
0.996 : 0.996
Volume of oxygen needed:
PV = nRT
V = nRT/P
V = 0.996 mol × 0.0821 atm.L/mol.K × 273.15 K / 1 atm
V = 22.34 L
There must be an intramolecular force. The oxygen atoms are produced as a result of the breakdown of oxygen molecules. Intramolecular force is necessary to stop the oxygen (O2) in the air from changing into the O atom.
Which force causes attraction between O2 molecules?
The result is the London dispersion force, a fleeting attractive attraction, which is created when the electrons in two neighboring atoms occupy positions that temporarily cause the atoms to form dipoles. This interaction is commonly described by the phrase "induced dipole-induced dipole attraction".
What is the difference between intramolecular forces and intermolecular forces which type is stronger?
In general, intramolecular forces are greater than intermolecular forces. Ion-dipole interaction exerts the strongest intermolecular force, followed by hydrogen bonds, dipole-dipole interaction, and London dispersion. Examples. Hydrogen bonding forces, London dispersion forces, and dipole-dipole forces are the three different kinds of intermolecular interactions. The three different kinds of intramolecular forces are metal bonds, ionic bonds, and covalent bonds.
Learn more about intramolecular forces: brainly.com/question/28170469
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NaCl and H2O.
The products are typically the elements/compounds on the right side of the equation or the right side of the arrow. The left side of the arrow would be the reactants of the equation.
Hope this helps!
