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11Alexandr11 [23.1K]
3 years ago
15

The graph below describes the journey of a train between two cities

Mathematics
2 answers:
vovangra [49]3 years ago
8 0

Answer:

200km/h^2, 125km, 62.5km/h

Step-by-step explanation:

For part a) just use the acceleration formula (change in velocity/time). For part b), remember that distance traveled is the area under the graph. This is because displacement is the integral of velocity, meaning that you integrate to find the area (i.e. displacement). Lastly, for part c), just apply speed = distance/time because in this case, acceleration is constant.

UkoKoshka [18]3 years ago
3 0

Answer:

Step-by-step explanation:

To find : Acceleration in first 15 min . Distance between two cities  Average speed of journey

Solution:

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                    Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Distance between two cities

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

Average Speed of journey = 125/2  = 62.5  km/hr

Acceleration in first 15 min = 200  km/h²

Distance between two cities = 125 km

Average Speed of journey =  62.5  km/hr

Hope this helps..

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vredina [299]

Answer:

x = 49.8^\circ\\y = 54.6^\circ

Step-by-step explanation:

Kindly refer to the image attached in the answer region for labeling of triangle.

<em>AB </em><em>= 16 </em>

<em>BC </em><em>= 19</em>

<em>AC </em><em>= 15 </em>

\angle ABC = x^\circ\\\angle ACB = y^\circ

We have to find the <em>angles </em><em>x</em> and <em>y</em> i.e. \angle B \text{ and }\angle C.

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<em>b</em> is the side opposite to \angle B  and

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\Rightarrow cos x = \dfrac{19^{2}+16^{2}-15^{2}}{2 \times 19 \times 16}\\\Rightarrow cos x = \dfrac{392}{608} \\\Rightarrow x = 49.8^\circ

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Answer:

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Step-by-step explanation:

Applying,

A = 1/2bh....................... Equation 1

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But, from the diagram,

tanФ = 20/b

b = 20/tanФ.................. Equation 2

Substitute equation 2 into equation 1

A = 1/2(20/tanФ)(h)................ Equation 3

Given: h = 20 m, Ф = 40°

Substitute these values into equation 3

A = 1/2(20×20)/tan40°

A = 200/tan40°

A = 238.35 m²

If the seed company recommends planting approximately 350 grass seeds per square meter,

Therefore,

Number of grass seed need = (350×238.35)

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Please help I have no idea how to do this!
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Answer:

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Step-by-step explanation:

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Check our work:

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3 years ago
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