All categories

3 years ago

Factor completely 2x2 − 32.

Mathematics

2 answers:

kvv77 [185]3 years ago

5 0

Answer:

2(1x1-16)

Step-by-step explanation:

1. Find the gcf (greatest common factor) which is 2

2. Divide by each of the factors and put it inside of the parentheses

zaharov [31]3 years ago

5 0

Answer:

2 *(x-4)(x+4)

Step-by-step explanation:

Using difference of square:

a^2-b^2=(a-b)(a+b)

GCF is the largest number that divide the given polynomial or expression.

Given the expression:

2x^2-32

We have to completely factor the expression.

GCF of 2x^2 and 32 is, 2

then;

2 *(x^2-16)

Using difference of square

2 * (x-4)(x+4)

therefore, the completely factor of 2x^2-32 is, 2 * (x-4)(x+4)

I hope this helps. If you have any more questions, please feel free to post them and someone will be able to help you, whether it's myself or others. Please leave a like, rating, and if possible, Brainliest. Have a great day!

You might be interested in

Help please! This is hard

Nutka1998 [239]

Answer: 200°C + 273.15 = 473.15K

300K − 273.15 = 26.85°C

I hope this helps bye

7 0

3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

4 years ago

1. L.B. Johnson Middle School held a track and field event during the school year. The chess club sold various drink and snack i

iris [78.8K]

Divide $2,673 by 486

6 0

3 years ago

Read 2 more answers

Use complete sentences to describe the domain of the consine function.

Anika [276]

Can you provide a picture ?? or some sort of context

3 0

3 years ago

Read 2 more answers

Need help figuring out this problem!

JulijaS [17]

6[13-2(4+1)]

Solve what is in the bracket first.
Parenthesis first.

6[13-8-2]
6(3)
18

7 0

3 years ago