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tatyana61 [14]
3 years ago
12

Factor completely 2x2 − 32.

Mathematics
2 answers:
kvv77 [185]3 years ago
5 0

Answer:

2(1x1-16)

Step-by-step explanation:

1. Find the gcf (greatest common factor) which is 2

2. Divide by each of the factors and put it inside of the parentheses

zaharov [31]3 years ago
5 0

Answer:

2 *(x-4)(x+4)

Step-by-step explanation:

<u>Using difference of square: </u>

a^2-b^2=(a-b)(a+b)

<u>GCF is the largest number that divide the given polynomial or expression. </u>

Given the expression:

2x^2-32

<u>We have to completely factor the expression. </u>

GCF of 2x^2 and 32 is, 2

then;

2 *(x^2-16)

<u>Using difference of square </u>

2 * (x-4)(x+4)

therefore, the completely factor of 2x^2-32 is, 2 * (x-4)(x+4)

I hope this helps. If you have any more questions, please feel free to post them and someone will be able to help you, whether it's myself or others. Please leave a like, rating, and if possible, Brainliest. Have a great day!    

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Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
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Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

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And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

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