Let m be the side length of the fourth smallest possible square with integer value of its area, and let n be the sum of all prim
1 answer:
Answer:
510
Step-by-step explanation:
It's assumed 0 is not an integer.
M is obviously 2. The area of a square is the square of its side length. If this area must be an integer, then it must be the fourth integer, which is 4. The side length,
A prime number is a positive integer which can be divided exactly by only itself and 1. In fact, it has only those two factors. The last statement excludes 1 as a prime number. Hence, the prime numbers less than 10 are 2, 3, 5 and 7. Their sum is .
To evaluate ,
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Answer:
Step-by-step explanation:
We have the problem:
6 2/3 can be written as (6 + 2/3), and 3 1/5 can be written as (3 + 1/5). So, we can then use the distributive property:
Now, we need to combine the fractions by finding a common denominator. Here, the common denominator is 3 * 5 = 15:
Finally, we add 18 to 1 11/15:
Thus, the answer is .
Hope this helps!