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gladu [14]
3 years ago
6

The scale on a map is 1 inch per 150 miles. The map shows the town of Bluebell is 3.5 inches away

Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

525

Step-by-step explanation:

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The slope of the line that passes through the points is 0 slope. That is B is the answer.

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Is 0.12 a rational number
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Yes .12 is a rational number
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Find the mean median mode<br> 12,9,12,11,10,18,7,19,13,19
Nady [450]

Mean : The average of all the data in a set.

Median : The value in a set which is most close to the middle of a range.

Mode : The value which occures most frequently in a data set.

12,9,12,11,10,18,7,19,13,19

Mean = 13 (Average)

Median = 12 (Middle)

Mode = 12, 19 (most common)

8 0
4 years ago
What is the area of one face of a cube if the cube measures 6.6 inches on each side?
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Since all sides of a cube are congruent, the area of one face of the cube can be found using the area formula of a square. A= length x width

Since all sides are the same, you can fill in your formula as:
6x6
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6 x 6= 36

Then, make sure you use the proper units for area and your final answer is
36 in^2
8 0
4 years ago
The table shows the viscosity of an oil as a function of temperature. Identify a quadratic model for the viscosity, given the te
777dan777 [17]

Answer:

The viscosity at 140°C is predicted to be 7.2

Step-by-step explanation:

The function that model the relationship between viscosity and temperature = Quadratic model

The general form of a quadratic equation is y = a·x² + b·x + c

Therefore, we have;

When y = 10.8, x = 110, which gives;

10.8 = a·110² + b·110 + c = 12100·a + 110·b + c

10.8 = 12100·a + 110·b + c

When y =8.2, x = 130

8.2 = a· 130² + b· 130 + c = 16900·a + 130·b + c

8.2 = 16900·a + 130·b + c

When y = 160, x = 5.8

5.8 = a·160² + b·160 + c = 25600·a + 160·b + c

5.8 = 25600·a + 160·b + c

The three equations above can be listed as follows;

10.8 = 12100·a + 110·b + c

8.2 = 16900·a + 130·b + c

5.8 = 25600·a + 160·b + c

Solving using matrices gives;

\begin{bmatrix}12100 & 110 & 1\\ 16900 & 130 & 1\\ 25600 & 160 & 1\end{bmatrix} \begin{bmatrix}a\\ b\\ c\end{bmatrix} = \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

\begin{bmatrix}a\\ b\\ c\end{bmatrix} = -\dfrac{1}{3000}\begin{bmatrix}3 & -5 & 2\\ -867 & 1350 & -480\\ 62400 & -88000 & 28600\end{vmatrix} \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

From which we have;

a = 0.001, b = -0.37, c = 39.4

Substituting gives;

y = 0.001·x² - 0.37·x + 39.4

When x = 140

y = 0.962·140² - 0.37·140 + 39.4= 7.2

The viscosity at 140°C = 7.2.

8 0
3 years ago
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