All categories

2 years ago

Find the least common denominator (LCD) of 1/20 and 11/30

Mathematics

2 answers:

Sergeu [11.5K]2 years ago

5 0

Answer:

Step-by-step explanation:

To find the LCD, all you have to do is find the least common multiple (LCM) of the two denominators.

The fractions are already reduced, so you have to find the LCM of 20 and 30. The LCM of 20 and 30 is 60.

20 and 30 are easy numbers, so you can just list the multiples out.

20: 20, 40, 60, etc.

30: 30, 60

The lists both have 60, so the LCM is 60.

Another way is to prime factorize the two numbers.

20: 2^2*5

30: 2*3*5

Then, take the non-repeating factor from the second number (3) and multiply that by 30, which is 60.

Mrrafil [7]2 years ago

3 0

Answer:

Step-by-step explanation:

LCD(1 /20 , 11 /30) = LCM(20, 30) = 22×3×5 = 60

1 /20 = 3 /60

11 /30 = 22 /60

You might be interested in

HELP I AM TIMED!!!!!!!!!!!!

ExtremeBDS [4]

Answer:

It is the last one 6a-4b+11

Explanation:

Hope this helps if u need clarification plz ask:)

5 0

1 year ago

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

Part 2) The surface area of the pyramid is $288\ cm^{2}$

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

$sin(x)=\frac{16}{20}$

$x=arcsin(\frac{16}{20})=53.13\°$

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

$b=2h$

$sin(45\°)=\frac{h}{6\sqrt{2}}$

$h=6\sqrt{2}(sin(45\°))=6\ cm$

Find the value of b

$b=2(6)=12\ cm$

Find the surface area

$SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}$

3 0

3 years ago

Pls answer “b” correctly and I will mark it has brainlist

Phoenix [80]

Since it is a slope, the equation of a slope is y=Mx+b. So you want to get b to that format. To do this, you need to isolate the y on the left. To do this, you simply add 2x to both sides. Your final answer will be y=2x+7. Hope this helps!

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=4%20%5Ctimes%20%20%7B8%7D%5E%7Bx%20%2B%201%7D%20%20%3D%20%20%7B2%7D%5E%7B2x%7D%20" id="TexForm

Olin [163]

Answer:

$- 2$

Step-by-step explanation:

2^2×2^3(x+1)=2^2x

same base cancel,you will get

2+3x+3=2x

take same variable then - or + you will get

$x = - 2$

4 0

2 years ago

Read 2 more answers

Plz help me. I'm confused on hw

r-ruslan [8.4K]

Answer: Yes by SAS

Why: they have two equal sides makes by the dashes and two 90 degree angles in the same places on both triangles meaning that the other side next to the 90 degree angle had to be equal as will

Hope this helps :D

4 0

2 years ago