Answer:
7 years 11 months
Step-by-step explanation:
The future value formula for the value of a principal P invested at annual rate r compounded n times yearly for t years is ...
FV = P(1 +r/n)^(nt)
For the given numbers, we want to find t:
6000 = 3700(1 +.062/2)^(2t)
Dividing by 3700 and taking the logarithm, we get ...
6000/3700 = 1.031^(2t)
log(60/37) = 2t·log(1.031)
Dividing by the coefficient of t gives ...
t = log(60/37)/(2log(1.031)) ≈ 7.92 . . . . . years
It will take about 7 years 11 months for the investment to grow to $6000.
Answer:
B
Step-by-step explanation:
b is the correct answer
<h3>
Answer: (n-1)^2</h3>
This is because we have a list of perfect squares 0,1,4,9,...
We use n-1 in place of n because we're shifting things one spot to the left, since we start at 0 instead of 1.
In other words, if the answer was n^2, then the first term would be 1^2 = 1, the second term would be 2^2 = 4, and so on. But again, we started with 0^2 = 0, so that's why we need the n-1 shift.
You can confirm this is the case by plugging n = 1 into (n-1)^2 and you should find the result is 0^2 = 0. Similarly, if you tried n = 2, you should get 1^2 = 1, and so on. It appears you already wrote the answer when you wrote "Mark Scheme".
All of this only applies to sequence A.
side note: n is some positive whole number.
Yes he has enough index cards for all students
Answer:
900
Step-by-step explanation:
4F + F =1125
5F = 1125
F=225
C=4F
C=4(225)=900
900 + 225=1125
