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2 years ago

Three teachers share 7 brownies equally how much does each teacher get?

Mathematics

2 answers:

sweet [91]2 years ago

4 0

A: 1 whole and 1 third

dybincka [34]2 years ago

4 0

Answer:

C:2 wholes 1 third

Step-by-step explanation:

$\frac{7}{3} =2\frac{1}{3}$

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Choose a number between 67 and 113 that is a multiple of 3, 9, and 12

Anestetic [448]

72 is multiples of 3,9, and 12

3 0

2 years ago

It took Brian 6 hours to drive to the sales conference. He took the same route on the way back home, but

g100num [7]

Answer: 54 mph

Step-by-step explanation:

d-the distance

s+9 - the speed to the conference

d=6*(s+9)

s- is the speed on the way back home

d=7*s

so 6*(s+9)=7*s

6s+54=7s

-6s -6s

54= 7s-6s

s=54 mph

6 0

3 years ago

A explanation also would be super helpful and very appreciated!

xxTIMURxx [149]

Answer:

26%

Step-by-step explanation:

345. 24 - 274 = 71.24

71.24 / 274 =0.26

0.26 * 100 = 26

8 0

3 years ago

Which factoring method would be best to factor x^2 - 9?

Vinil7 [7]

Answer:

D. difference of squares

Step-by-step explanation:

Both of the terms x^2 and 9 are squares, so their difference is the difference of squares. The factorization of that is a "special form" that can be usefully memorized.

a^2 -b^2 = (a -b)(a +b)

x^2 -9 = (x -3)(x +3)

8 0

2 years ago

Find the perimeter of the triangle defined by the coordinates (7, 1), (-6, 1), and (10, 6). (Round to nearest tenth)

matrenka [14]

Answer:

$35.6\ units$

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the length of the three sides

Let

$A(7, 1), B(-6, 1), C(10, 6)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(7, 1), B(-6, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(-6-7)^{2}}$

$d=\sqrt{(0)^{2}+(-13)^{2}}$

$dAB=13\ units$

Find the distance BC

$B(-6, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10+6)^{2}}$

$d=\sqrt{(5)^{2}+(16)^{2}}$

$dBC=16.8\ units$

Find the distance AC

$A(7, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10-7)^{2}}$

$d=\sqrt{(5)^{2}+(3)^{2}}$

$dAC=5.8\ units$

Find the perimeter

$P=dAB+dBC+dAC$

$P=13+16.8+5.8=35.6\ units$

4 0

3 years ago