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soldier1979 [14.2K]
3 years ago
5

I would like to know what kind of algebra that i was ?

Mathematics
2 answers:
Mila [183]3 years ago
7 0

Answer:

basic algebra

This chapter contains elementary algebra tutorials on the following topics:

1. Adding and Subtracting Algebraic Expressions, shows you how to do problems like: Simplify: −2[−3(x − 2y) + 4y].

2. Multiplication of algebra expressions, has examples like:

Expand (2x + 3)(x2 − x − 5).

3. Division of algebraic expressions, for example: (12a2b) ÷ (3ab2)

4. Solving Equations, like this one: 5 − (x + 2) = 5x.

5. Formulas and Literal Equations, which shows how to solve an equation for a particular variable.

6. Applied Verbal Problems shows why we are doing all this.

Step-by-step explanation:

HAHAHAHAHAHA LOL XD

zzz [600]3 years ago
4 0

Answer:

algebra  1

Step-by-step explanation:

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How to solve this ?
Serga [27]

-x-3y=-26

6x+3y=21

---------------

3y cancels out.

-x=-26

6x=21

--------------

5x=-5

x=-1


6 0
3 years ago
In order for this ratio of volumes to be true, what measurements would have to be equal in all 3 solids?
Neporo4naja [7]

The measurements of the figures that should be equal in order for the ratio of volumes between the volumes of the cone, sphere, and cylinder of 1:2:3 to be true is; The radius and the height

<h3>What is a ratio?</h3>

A ratio is a comparison between the magnitudes or measurements of items, expressing the number of times one item in the ratio is contained within another item in the ratio.

The formula for the volume of a cone, V_p is, V_p = (1/3)·π·r₁²·h₁

The formula for the volume of a sphere, V_s, is V_s = (4/3)·π·r₂³

The formula for the volume of a cylinder, V_c, is V_c = π·r₃²·h₃

The ratio of the volumes in the question is 1:2:3

Therefore; The volume of the sphere is twice the volume of the cone, and the volume of the cylinder is three times the volume of the cone, which indicates;

(4/3)·π·r₂³ = 2 × (1/3)·π·r₁²·h₁...(1)

π·r₃²·h₃ = 3 × (1/3)·π·r₁²·h₁...(2)

Equation (1) indicates that we have;

(4/3)·π·r₂³ = 2 × (1/3)·π·r₁²·h₁

Where, h₁ = 2·r₂, we get;

(4/3)·π·r₂³ = 2 × (1/3)·π·r₁²·(2·r₂) = (4/3)·π·r₁²·r₂

Therefore; r₁ = r₂, and the diameter of the sphere is equal to the height of the cone

The radius of the cone is equal to the radius of the sphere

Equation (2) indicates;

π·r₃²·h₃ = 3 × (1/3)·π·r₁²·h₁ = π·r₁²·h₁

Therefore;

r₃²·h₃ = r₁²·h₁

r₃ = r₁

h₃ = h₁

The radius of the cone = The radius of the cylinder

The height of the cone = The height of the cylinder

  • The ratio of the volumes, 1 : 2 : 3 is true when the measurements of the radius and the height are equal for all three solids.

Learn more about the volume of regular solids here:

brainly.com/question/15316195

#SPJ1

4 0
1 year ago
Claire deposited $500 into a savings account that earns 2.5% annual simple interest. If she keeps this amount in the account for
Snezhnost [94]

Answer:

Claire will earn $25 in interest after 2 years.

7 0
3 years ago
In the following​ exercise, does the problem involve permutations or​ combinations? Explain your answer. One hundred people purc
Blizzard [7]

Answer: Permutation is involved , since order of prizes matters.

The number of different ways the prizes can be​ awarded =95060

Step-by-step explanation:

Given : Total number of people purchase lottery tickets =100

The number of prizes = 3

Since each prize can be claimed by only one person.

So order matters here, there for we use permutations .

The number of permutations of n objects taken m at a time is given by :-

^nP_m=\dfrac{n!}{(n-m)!}

Then, the number of different ways the prizes can be​ awarded :-

^{100}P_{3}=\dfrac{100!}{(100-3)!}=\dfrac{100!}{97!}\\\\=100\times98\times97=950600

0 0
3 years ago
Need ASAP if you don’t know the answer don’t answer
gogolik [260]

Answer:

254.47

Step-by-step explanation:

4 0
3 years ago
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