Answer:
From given, we have,
Paul says he is 16 inches shorter than 1 1/2 times Theresa's height.
Steve says he's 6 inches shorter than 1 1/3 times Theresa's height.
Let the height of Theresa be "x" inches.
So, we get,
For Paul, 1 1/2 x - 16 = T
⇒ 3/2 x - 16 = T ......(1)
For Steve, 1 1/3 x - 6 = T
⇒ 4/3 x - 6 = T .........(2)
equating equations (1) and (2), we get,
3/2 x - 16 = 4/3 x - 6
6 - 16 = 4/3 x - 3/2 x
-10 = (8 - 9)/6 x
-60 = -x
x = 60 inches.
Therefore, Theresa is 60 inches tall.
Answer:
Third quartile (Q₃) = 46.75 minutes.
Therefore, Option (c) is the correct answer.
Step-by-step explanation:
Given: Mean (μ) = 40 minutes and S.D (σ) = 10 minutes
To find : Third quartile (Q₃) = ?
Sol: As the third quartile of normal distribution covers the 75% of the total area of the curve and first quartile covers the 25% of the total area of the curve. Then with the help of z score table, the value represented the third quartile of the normal distribution is:
Q₃ = μ + 0.675 σ
Now by substitution the value of mean and standard deviation,
Q₃ = 40 + 0.675 × (10)
Q₃ = 40 + 6.75
Q₃ = 46.75
Therefore, the third quartile (Q₃) = 46.75. So, option (c) is the correct answer.
In an equilateral triangle (all sides and anges are equal)
angles are 60 degrees each
The total length of a line segment is the sum of the lengths of its parts.
MQ = MK + KQ . . . . . . express the relationship between the segments
15 in = 7 in + KQ . . . . . fill in the given information
(15 - 7) in = KQ . . . . . . .subtract 7 in
KQ = 8 in . . . . . . . . . . . simplify
The measurement of KQ is 8 inches.
Answer:
I dont know sorry look so complicated
