Answer: I don’t know why don’t you think
Step-by-step explanation:
<h2>
The required positive number is 7.</h2>
Step-by-step explanation:
Let the number = x
To find, the positive number = ?
According to question,
![x^{2}-28=3x](https://tex.z-dn.net/?f=x%5E%7B2%7D-28%3D3x)
⇒
- 3x - 28 = 0
By Factorisation method,
⇒
- 7x + 4x - 28 = 0
⇒ x(x - 7) + 4(x - 7) = 0
⇒ (x - 7)(x + 4) = 0
⇒ x - 7 = 0 or, x + 4 = 0
⇒ x = 7 or, x = - 4 [ - 4 is a negative number)
⇒ x = 7
Thus, the required positive number is 7.
Answer:
1. 0.472
2. 0.25
Step-by-step explanation:
1. reduce the fraction with 3 = 1\4 + 2\9
write all numerators above the Least common denominator 36 =9 + 8\36
Add numbers = 17\36 and the alternate form is 0.472
2. Divide the numerator and denominator by three = 3 ÷ 3\12 ÷ 3 = 0.25
I can't do the others now I have an exam(sorry)
The answer is:
545>322
540 <997
The logic is there are six sides to each die, so for each number on one die you can pair with six different numbers on the other die. Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12.