83 x 72 = 5,976. 82 x 73 = 5,986. The way to do this is to take the two biggest numbers and use them in the tens place. Then take the other numbers and put them in the ones space. Then switch the ones slot numbers around to get two different numbers over 5000.
Answer:
See explanation
Step-by-step explanation:
Triangle ABC ha vertices at: A(-3,6), B(0,-4) and (2,6).
Let us apply 90 degrees clockwise about the origin twice to obtain 180 degrees clockwise rotation.
We apply the 90 degrees clockwise rotation rule.




We apply the 90 degrees clockwise rotation rule again on the resulting points:



Let us now apply 90 degrees counterclockwise rotation about the origin twice to obtain 180 degrees counterclockwise rotation.
We apply the 90 degrees counterclockwise rotation rule.




We apply the 90 degrees counterclockwise rotation rule again on the resulting points:



We can see that A''(3,-6), B''(0,-4) and C''(-2,-6) is the same for both the 180 degrees clockwise and counterclockwise rotations.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Midpoint Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points from graph.</em>
Point (-6, 5)
Point (5, -7)
<u>Step 2: Find Midpoint</u>
Simply plug in your coordinates into the midpoint formula to find midpoint
- Substitute [MF]:

- Add/Subtract:

- Divide:

ANSWER
Yes it is very true
<u>EXPLANATION</u>
If the two equations intersect at
then this point must satisfy the two equations.

We substitute
in to erquation (1)




We now substitute
in to erquation (2) also



Since the point satisfy all the two equations, it is true that they intersect at 