The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
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Answer:
56x6+3x
Step-by-step explanation:
3x+7x(8x5)
3x+56x6
Answer:
1) y=8/3=2 2/3 2) x=4 3) x+10
Step-by-step explanation:
1) 10+5-7=3y
Calculate the sum or difference.
8=3y
Swap the sides of the equation.
3y=8
Divide both sides by 3.
y=8/3=2 2/3
2) -10x+5x+5=-15
Collect like terms.
-5x+5=-15
Move the constant to the right-hand side and change the sign.
-5x=-15-5
Calculate the difference.
-5x=-20
Divide both sides by -5.
x=4
3) 3x+2x-4x+10
Collect like terms.
(3+2-4)x+10
Calculate the sum or difference.
1x+10
When the term has a coefficient of 1, it doesn't have to be written.
x+10
Hope this helps :)
The procedure to squaring a two digit number is by multiplying the first number by a integer greater than the number and putting 25 beside it.
Finding the Square of a Value is a simple method. Multiply the specified integer by itself to determine the square number. The square term is always represented as an integer multiplied by two. For example, the square of 5 is 25 multiplied by 5, giving 5×5 = 5² = 25.
What if we want to calculate the square root of a two-digit number . It might be a little challenging. Ordinary multiplication cannot be used to compute the square of two-digit values. This article will show us how to calculate the precise square of such integers.
Simply multiply a single-digit number by itself to find its square. Furthermore, by memorizing the tables from 1 to 10.
We taught about two triangles and how to find the point of any base of a triangle given the other two sides using Pythagoras' theorem.
A right triangle has three sides: the hypotenuse, perpendicular, and base. Pythagoras' theorem states that
Hypotenuse² = Perpendicular² + Base².
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4 1/5
hope this helped, im better at algebra tho :)