Answer:
Simplifying
(20m + 3) + -1(7m + -5) = 0
Reorder the terms:
(3 + 20m) + -1(7m + -5) = 0
Remove parenthesis around (3 + 20m)
3 + 20m + -1(7m + -5) = 0
Reorder the terms:
3 + 20m + -1(-5 + 7m) = 0
3 + 20m + (-5 * -1 + 7m * -1) = 0
3 + 20m + (5 + -7m) = 0
Reorder the terms:
3 + 5 + 20m + -7m = 0
Combine like terms: 3 + 5 = 8
8 + 20m + -7m = 0
Combine like terms: 20m + -7m = 13m
8 + 13m = 0
Solving
8 + 13m = 0
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + 13m = 0 + -8
Combine like terms: 8 + -8 = 0
0 + 13m = 0 + -8
13m = 0 + -8
Combine like terms: 0 + -8 = -8
13m = -8
Divide each side by '13'.
m = -0.6153846154
Simplifying
m = -0.6153846154Step-by-step explanation:
We know that m<JKL = m<JKM + m<MKL
Let's substitute the values from the picture into our equation above.
10x - 11 = 43 + 8x - 20
Combine like terms.
10x - 11 = 8x + 23
Subtract 8x from both sides and add 11 to both sides.
2x = 34
Divide both sides by 2
x = 17
m<MKL = 8x - 20 = 8(17) - 20 = 136 - 20 = 116 degrees.
m<JKL = 10x - 11 = 10(17) - 11 = 170 - 11 = 159 degrees.
The vertex form of all expressions is given below.
We have given that the expressions
We have to write the function in vertex form.
<h3>What is the vertex form of the equation?</h3>
The vertex form of a quadratic function is given by f (x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.
Therefore the first equation
it can be written as
The second equation can be written as
vertex for is,
The third equation is,
Vertex form is,
Forth equation is,
Vertex form is,
To learn more about the vertex form visit:
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How much was each candle worth?? if he sold and equal amount of both, he would have sold 72 of both candles.
Answer: D, -13<-10
Step-by-step explanation:
Which ever way the open part of the '<' is facing, means that it is greater than the other number.
-13 is smaller than -10 so the open part of the symbol would face towards -10 and the pointy part would fact towards the -13.
Hope this helps :)
