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spayn [35]
3 years ago
7

Five million bacteria live in an organism. The doubling period is 1.5 hours. How many will there be after:

Mathematics
1 answer:
finlep [7]3 years ago
8 0
We write the generic exponential equation:
 y = A (b) ^ t
 Where,
 A: initial population
 B: growth rate
 t: time in hours.
 Substituting values we have:
 y = 5 (2) ^ ((1 / 1.5) * t)
 For t = 9 hours we have:
 y = 5 (2) ^ ((1 / 1.5) * 9)
 y = 320 million
 For t = 24 hours (one day) we have:
 y = 5 (2) ^ ((1 / 1.5) * 24)
 y = 327680 million
 For t = 2 hours we have:
 y = 5 (2) ^ ((1 / 1.5) * 2)
 y = 12.5992105 million
 Answer:
 
a) t hours?
 
y = 5 (2) ^ ((1 / 1.5) * t)
 
b) 9 hours?
 
y = 320 million
 
c) 1 day?
 
y = 327680 million
 
d) 2 hours?
 
y = 12.5992105 million
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Please and thank you SM!!
otez555 [7]

Answer:

Step-by-step explanation:

∠A=∠B

4X+7=5X-3

X=7+3=10

5*10-3=50-3=47

6 0
3 years ago
Determine the expression you can substitute for x in 4x + 2y= 3
rusak2 [61]

Answer:


x=

−1 /2 y+ 3 /4


Step-by-step explanation:

Let's solve for x.

4x+2y=3

Step 1: Add -2y to both sides.

4x+2y+−2y=3+−2y

4x=−2y+3

Step 2: Divide both sides by 4.

4x /4

=

−2y+3 /4

x=

−1 /2 y+ 3 /4

7 0
4 years ago
the area of a regular octagon is 25 cm. what is the area of regular octagon with sides five times as large?
SIZIF [17.4K]
I think your answer is 125 cm. Good Luck.
5 0
3 years ago
carl has 42inches of ribbon & tino has 2.5 feet of rubbon.whats tge total lengh of rubbon the three friends have in inches,f
Gre4nikov [31]
50. First and foremost, in the given situation, there are only 2 person, Carl and Tino. Not Three. => Carl has 42 inches of ribbon => Tino has 2.5 feet of ribbon. Now, we need to convert this into yard, feet and inches, let’s have yard first => 42 inches = 1.17 yard => 2.5 feet = 0.83 yard => 1.17 + 0.83 => 2 yards in total Now, the feet => 42 inches = 3.5 feet => 2.5 feet => 3.5 feet + 2.5 Feet => 6 feet in total Next is the inches => 42 inches => 2.5 feet = 30 inches => 42 inches + 30 inches = 72 inches in total
6 0
3 years ago
I start with $9-2x$ widgets. Each day, I produce $2x+1$ widgets, and destroy $3-x$ widgets. After three days, how many widgets a
ivann1987 [24]

Answer:

3+7x

Step-by-step explanation:

-We add the number of widgets produced in 3 days to the number originally owned:

T_{own}=(9-2x)+3(2x+1)\\\\=9-2x+6x+3\\\\=12+4x

#We the determine the widgets destroyed in 3 days:

T_{destroy}=3(3-x)\\\\=9-3x

#Subtract the widgets destroyed from the total owned to get what is left after 3 days:

Remain=T_{own}-T_{destroy}\\\\=(12+4x)-(9-3x)\\\\=12+4x-9+3x\\\\=3+7x

Hence, the number of widgets remaining after 3 days is 3+7x

5 0
3 years ago
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