Question

I start with $9-2x$ widgets. Each day, I produce $2x+1$ widgets, and destroy $3-x$ widgets. After three days, how many widgets am I left with, in terms of $x$?

Answer 1

Answer:

3+7x

Step-by-step explanation:

-We add the number of widgets produced in 3 days to the number originally owned:

$T_{own}=(9-2x)+3(2x+1)\\\\=9-2x+6x+3\\\\=12+4x$

#We the determine the widgets destroyed in 3 days:

$T_{destroy}=3(3-x)\\\\=9-3x$

#Subtract the widgets destroyed from the total owned to get what is left after 3 days:

$Remain=T_{own}-T_{destroy}\\\\=(12+4x)-(9-3x)\\\\=12+4x-9+3x\\\\=3+7x$

Hence, the number of widgets remaining after 3 days is 3+7x