He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix?
<span>You may write the equation as </span>
<span>(y-1)^2 = (1) (x+4) </span>
<span>(y-k)^2 = 4p(x-h), where (h,k) is the vertex </span>
<span>4p=1 </span>
<span>p=1/4 </span>
<span>k=1 </span>
<span>h=-4 </span>
<span>The directrix is a vertical line x= h-p </span>
<span>x = -4-1/4 </span>
<span>x=-17/4 </span>
<span>------------------------------- </span>
<span>What is the focal length of the parabola with equation y - 4 = 1/8x^2 </span>
<span>(x-0)^2 = 8(y-4) </span>
<span>The vertex is (0,4) </span>
<span>4p=8 </span>
<span>p=2 (focal length) -- distance between vertex and the focus </span>
<span>------------------------------- </span>
<span>(y-0)^2 = (4/3) (x-7) </span>
<span>vertex = (7,0) </span>
<span>4p=4/3 </span>
<span>p=1/3 </span>
<span>focus : (h+p,k) </span>
<span>(7+1/3, 0)</span>
<span>The weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 12. </span>
Answer:
its eighteen centimeters because
Step-by-step explanation:
6 divided by 1/3= 18
Answer:
-xy^6 +2y -6
Step-by-step explanation:
(-6x^2 y^8+12xy^3-36xy^2)
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6xy^2
Divide each term by 6 in the numerator and denominator
(-6/6x^2 y^8+12/6xy^3-36/6xy^2)
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6/6xy^2
-x^2y^8 +2xy^3 -6xy^2
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xy^2
Divide each term by x in the numerator and denominator
-x^2/xy^8 +2x/xy^3 -6x/xy^2
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x/xy^2
-xy^8 +2y^3 -6y^2
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y^2
Divide each term by y^2 in the numerator and denominator
Remember when dividing, we subtract the exponents
-xy^8/y^2 +2y^3/y^2 -6y^2/y^2
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y^2 /y^2
-xy^6 +2y^1 -6
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1
-xy^6 +2y -6
Answer:
what do you mean evaluate
Step-by-step explanation:
