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hichkok12 [17]
4 years ago
15

What is 1/6 divide by 1/3

Mathematics
2 answers:
Xelga [282]4 years ago
4 0

0.555555556 so that's it hope this helped

vekshin14 years ago
3 0

Answer:

0.5

Step-by-step explanation:

Because I said so

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1.3.12
jasenka [17]

Answer:

(0.5,-1.5)

Step-by-step explanation:

this is the numbers i got when I put it in...

m=({-\frac{1+0}{2}  , \frac{-5+2}{2})

(0.5,-1.5)

7 0
3 years ago
Read 2 more answers
Above is a table with missing terms. Come up with a possible common difference that makes sense and list the missing terms.
Rina8888 [55]

Answer:

common ratio:2 2. 18  3.36  4.72 equation: 4.5(2^x)

Step-by-step explanation:

144=2*2*2*2*3*3    9=3*3

the common ratio would be 2

2. 9*2=18

3. 18*2=36

4. 36*2=72

(check) 72*2=144

0. 9/2=4.5

equation: 4.5(2^x)

7 0
3 years ago
Which statement best describes a method that can be used to sketch the graph. y = |x - 2| a. Translate the graph of y = |x| two
ser-zykov [4K]

f(x) + n - translate the graph of f(x) n units up

f(x) - n - translate the graph of f(x) n units down

f(x + n) - translate the graph of f(x) n units left

f(x - n) - translate the graph of f(x) n units right

--------------------------------------------------------------------------

We have

y = |x - 2|

f(x) = |x| → f(x - 2) = |x - 2|

<h3>Answer: c. Translate the graph of y = |x| two units right.</h3>
6 0
3 years ago
What is greater 17 quarts or 4 gallons?
stepan [7]
17 quarts is greater. 4 gallons is equal to 16 quarts, right?
So 17 quarts would be greater than 4 gallons or 4.25 gallons
17 QUARTS IS GREATER.
5 0
3 years ago
Giving 100 points.
Nitella [24]

Answer:

1.   <u>Cost per customer</u>:  10 + x

     <u>Average number of customers</u>:  16 - 2x

\textsf{2.} \quad  -2x^2-4x+160\geq 130

3.    $10, $11, $12 and $13

Step-by-step explanation:

<u>Given information</u>:

  • $10 = cost of buffet per customer
  • 16 customers choose the buffet per hour
  • Every $1 increase in the cost of the buffet = loss of 2 customers per hour
  • $130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

<u>Part 1</u>

<u></u>

<u>Cost per customer</u>:  10 + x

<u>Average number of customers</u>:  16 - 2x

<u>Part 2</u>

The cost per customer multiplied by the number of customers needs to be <u>at least</u> $130.  Therefore, we can use the expressions found in part 1 to write the <u>inequality</u>:

(10 + x)(16 - 2x)\geq  130

\implies 160-20x+16x-2x^2\geq 130

\implies -2x^2-4x+160\geq 130

<u>Part 3</u>

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

\implies -2x^2-4x+160\geq 130

\implies -2x^2-4x+30\geq 0

\implies -2(x^2+2x-15)\geq 0

\implies x^2+2x-15\leq  0

\implies (x-3)(x+5)\leq  0

Find the roots by equating to zero:

\implies (x-3)(x+5)=0

x-3=0 \implies x=3

x+5=0 \implies x=-5

Therefore, the roots are x = 3 and x = -5.

<u>Test the roots</u> by choosing a value between the roots and substituting it into the original inequality:

\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144

As 144 ≥ 130, the <u>solution</u> to the inequality is <u>between the roots</u>:  

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.  

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an <em>increase </em>in cost.  It does not confirm that if the cost is reduced (less than $10) the number of customers <em>increases </em>per hour.]

<u>Cost per customer</u>:  

x =0 \implies 10 + 0=\$10

x=3 \implies 10+3=\$13

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0
2 years ago
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