All categories

3 years ago

Solve the system by using the elimination method.

Mathematics

1 answer:

Inessa05 [86]3 years ago

6 0

Answer:

(8, 4 )

Step-by-step explanation:

Given the 2 equations

5x - 5y = 20 → (1)

- 3x + 5y = - 4 → (2)

Add the 2 equations term by term to eliminate the y- term

2x + 0 = 16

2x = 16 ( divide both sides by 2 )

x = 8

Substitute x = 8 into either of the 2 equations and solve for y

Substituting into (2)

- 3(8) + 5y = - 4

- 24 + 5y = - 4 ( add 24 to both sides )

5y = 20 ( divide both sides by 5 )

y = 4

solution is (8, 4 )

You might be interested in

A survey claims that 9 out of 10 doctors recommend aspirin for their patients with headaches. to test this claim, a random sampl

gayaneshka [121]

8.3 out of 10 docters

7 0

3 years ago

Read 2 more answers

Number 2 rewrite as a single power

Paul [167]

Answer:

-625

Step-by-step explanation:

I think so..

4 0

3 years ago

(4x²+x) - (x²+2x)<br>I need help please

Alex

The answer is 3x-x :)

You just simplify the expression, (4x^2-x^2) - (x- (-2x))

5 0

3 years ago

Read 2 more answers

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago

Can somebody help me with these 3 problems

kirill [66]

I suggest downloading the app “conects”

7 0

3 years ago