Question

There are eight teams in a league. I’m how many ways can the teams finish first, second, and third?

Answer 1

Answer:

There are 336 ways can the teams finish first, second, and third

Step-by-step explanation:

Total no. of teams = 8

First prize is given to one of the 8 teams

So, no. of teams left for second prize = 8-1 =7

Second prize is given to one of the remaining 7 teams

So, no. of teams left for third prize = 7-1=6

So,the teams finish first, second, and third in no. of ways =$8 \times 7 \times 6$

The teams finish first, second, and third in no. of ways = 336

Hence there are 336 ways can the teams finish first, second, and third