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Katena32 [7]
3 years ago
12

Mr. Nelson is checking some of the school's sport balls to make sure they are in good shape and

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: air pressures of properly inflated sports balls.

<em>Average recommended psi Tolerance </em>

<em>(pounds per square inch) </em>

<em>Soccer ball 12.05 ±3.55 </em>

<em>Basketball 8.00 ±0.5  </em>

<em>Volleyball  4.44 ±0.18</em>

Each recommendation is expressed like the "average air pressure" ± "standard deviation of the recommended air pressure" so if you express it in inequality it will be:

X[bar]-S ≤ X ≤ X[bar]+S

So for each ball type, you can write it as:

<u>Soccer ball</u>

12.05-3.55 ≤ X ≤ 12.05+3.55

8.5 ≤ X ≤ 15.6

<u>Basketball</u>

8.00-0.5  ≤ X ≤ 8.00+0.5

7.5  ≤ X ≤ 8.5

<u>Volleyball</u>

4.44-0.18 ≤ X ≤ 4.44+0.18

4.26 ≤ X ≤ 4.62

I hope this helps!

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Answer:

A

Step-by-step explanation:

A is correct.  The graph of the basic exponential function neither touches nor crosses the x-axis, whereas a linear function does cross over and can be negative for some inputs.

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A rug maker is using a patter that is a rectangle with a length of 96 inches and a width of 60 inches. the rug maker wants to in
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With this in mind, we have that the original design is 96×60, where 90 is length and 60 is width, so it would simply be:
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3 years ago
Math 2 Of high school
Daniel [21]

Answer:

  • B. BC = 18 so ∆ABC ~ ∆DEF by SAS

Step-by-step explanation:

\bf \cfrac{AB}{DE}  =  \cfrac{BC}{EF}

  • \bf \cfrac{15}{10}  =  \cfrac{BC}{12}
  • \bf  \cfrac{3}{2}  =  \cfrac{BC}{12}
  • \bf BC =  \cfrac{3}{2}  \times 12
  • \bf 3 \times 6
  • \bf BC = 18
  • \bf \angle B = \angle \: E

So, ∆ABC ~ ∆DEF by SAS.

<h3><u>------------------------------------</u></h3>
7 0
2 years ago
Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

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So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
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