(7-4) *5/3 I need help *= multiply /= division
1 answer:
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Answer:
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Step-by-step explanation:
Answer:
60 times will they ring together at the same second in one hour excluding the one at the end.
Step-by-step explanation:
Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.
To find : How many times will they ring together at the same second in one hour excluding the one at the end?
Solution :
First we find the LCM of 3, 6, 10, 12 and 15.
2 | 3 6 10 12 15
2 | 3 3 5 6 15
3 | 3 3 5 3 15
5 | 1 1 5 1 5
| 1 1 1 1 1
So, the bells will ring together after every 60 seconds i.e. 1 minutes.
i.e. in 1 minute they rand together 1 time.
We know, 1 hour = 60 minutes
So, in 60 minute they rang together 60 times.
Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.
Answer:
see explanation
Step-by-step explanation:
To find the x- intercepts set y = 0, that is
- 2x² - 9x + 5 = 0
To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term that sum to give the coefficient of the x- term.
product = - 2 × 5 = - 10 and sum = - 9
The factors are - 10 and + 1
Use these factors to split the middle term
- 2x² - 10x + x + 5 = 0 ( factor the first/second and third/fourth terms )
- 2x(x + 5) + 1(x + 5) ( factor out (x + 5) )
(x + 5)(- 2x + 1) = 0
equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
- 2x + 1 = 0 ⇒ x =
x-intercepts are x = - 5 and x =