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3 years ago

Which quantity is proportional to 35/80

Mathematics

1 answer:

Talja [164]3 years ago

6 0

Answer:

35/80

u want to find a number that is proportional to 35/80, then all u need is a number that is equivalent...another words, if it is proportional, it is an equivalent fraction to 35/80.

there can be several answers to this...such as 35/80 reduces to 7/16...so 7/16 is proportional....or if u multiply numerator and denominator by the same number, u will find a proportional number...

example :

35/80 * 2/2 = 70/160...this is proportional

35/80 * 3/3 = 105/240...this is proportional

35/80 * 4/4 = 140/320...this is also proportional

and so on....

so without giving us any answer choices, there can be many numbers to choose from

You might be interested in

У=-3x+3<br> y = -9x + 15

julia-pushkina [17]

Answer:

(2, - 3 )

Step-by-step explanation:

Given the 2 equations

y = - 3x + 3 → (2)

y = - 9x + 15 → (2)

Substitute y = - 3x + 3 into (2)

- 3x + 3 = - 9x + 15 ( add 9x to both sides )

6x + 3 = 15 ( subtract 3 from both sides )

6x = 12 ( divide both sides by 6 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (1)

y = - 3(2) + 3 = - 6 + 3 = - 3

solution is (2, - 3 )

8 0

2 years ago

Which function has zeros at x = 10 and x = 2? f(x) = x2 – 12x + 20 f(x) = x2 – 20x + 12 f(x) = 5x2 + 40x + 60 f(x) = 5x2 + 60x +

4vir4ik [10]

To find the correct function, just plug in 10 and 2 to see if the function equals zero with both numbers.

f(x)=x^2-12x+20
f(10)=100-120+20
f(10)=0 --> that's what we want, so let's check the other number

f(x)=x^2-12x+20
f(2)=4-24+20
f(2)=0 --> perfect. this function has zeros at both x=10 and x=2

The function that has zeros at both x=10 and x=2 is f(x)=x^2-12x+20.

5 0

2 years ago

Read 2 more answers

From a circular cylinder of diameter 10 cm and height 12 cm are conical cavity of the same base radius and of the same height is

Nataliya [291]

<h3>Volume of the remaining solid = 628 cm^2</h3>

<h3>Whole surface area = 659.4 cm^2</h3>

Step-by-step explanation:

Now, Given that:-

Diameter (d) = 10 cm

So, Radius (r) = 10/2 = 5cm

Height of the cylinder = 12cm.

$volume \: of \: the \: cylinder \: = \pi {r}^{2} h$

$= > \pi \times {5}^{2} \times 12 {cm}^{3} = 300\pi {cm}^{3}$

Radius of the cone = 5 cm.

Height of the cone = 12 cm.

$slant \: height \: of \: the \: cone \: = \sqrt{ {h}^{2} + \: {r}^{2} }$

$= > \sqrt{ {5}^{2}+{12}^{2} } cm \: = 13cm$

Volume of the cone = 1/3 *πr^2h

$= > \frac{1}{3} \pi \times {5}^{2} \times 12 {cm}^{3} = 100\pi {cm}^{3}$

therefore, the volume of the remaining solid

$= 300\pi {cm}^{3} - 100\pi {cm}^{3} \\ = 200 \times 3.14 {cm}^{3} = 628 {cm}^{3}$

Curved surface of the cylinder =

$2\pi \: rh \: = 2\pi \times 5 \times 12 {cm}^{2} \\ = 120\pi {cm}^{2} .$

$curved \: surface \: of \: the \: cone \: = \pi \: rl \\ = \pi \times 5 \times 13 {cm}^{2} \\ = 65\pi {cm }^{2} \\ area \: of \: (upper)circular \: base \: \\ of \: cylinder \: = \\ = \pi \: {r}^{2} = \pi \times {5}^{2}$