A = -3
nth term (u_n) = rn -3, where r = difference between each term
u_1 = -3
u_15 = 53 = 15r -3
u_15 = 56 = 15r
u_15 = 56 / 15 = r
u_n = (56/15)n - 3
Answer:
Step-by-step explanation:
Given that A cereal company claims that the mean weight of the cereal in its packets is 14 oz
Test the claim at the 0.01 significance level.H0: μ = 14 oz. H1: μ 14 oz.
Parameter Value
Mean 14.050
SD 0.346
SEM 0.122
N 8
90% CI 13.818 to 14.282
95% CI 13.760 to 14.340
99% CI 13.621 to 14.479
Minimum 13.6
Median 14.05
Maximum 14.6
Test statistic: t = 0.408
Critical values: t = ±3.499.
Since test statistic falls within the critical values, we accept the null hypothesis at 1% significance.
Fail to reject H0. There is not sufficient evidence to warrant rejection of the claim that the mean weight is 14 ounces.
Assume that you plan to use a significance level of α = 0.05 to test the claim that p1 = p2, Use the given sample sizes and numbers of successes to find the pooled estimate p. n1 = 100 n2 = 100 x1 = 33 x2 = 36
proportion difference = 0.03
Answer:
true
Step-by-step explanation:
txt me on brainly if u need more help <3
Answer: 2.
Step-by-step explanation: Don't reject H0, we can't conclude cause of the sales and the aftermath.
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