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Bess [88]
3 years ago
12

1. The weights of 30 students in a class ( in Kg ) are as follows. 42 , 52, 46 ,63, 47 ,40,50,63,52, 57,40,47,55 ,52, 49, 42,56,

51 ,48,47, 44,54, 54,62, 60,58,56,60,58,53.
Answer the following questions:
What weight range do most students lie in?​
Mathematics
2 answers:
kolbaska11 [484]3 years ago
8 0

Answer:

47 to 58 Kg.

Step-by-step explanation:

First arrange in ascending order:

40 40 42 42 44 46 47 47 48 49 50 51 52 52 52 53 54 54 55 56 56 57  58 58 60 60 62 63 63

The median value is 52.5.

The lower quartile is 47  and the higher quartile is 58.

Nat2105 [25]3 years ago
7 0

Answer:

Most of the students lie in the range of 50-60.

Step-by-step explanation:

Arrange all the data ib ascending order like 40, 40, 42, 42... and so on.

Assign the data to their respective ranges.

For example: 40 belongs to 40-50 range.

Also note that the maximum number in a range belongs to the next range as 50 does not belong in 40-50 it belongs in 50-60 range.

After assigning the values count the numbers of values in each range.

The range having the max. quantity of students is the final answer.

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Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among
Olegator [25]

Answer:

a) X[bar]₁=  1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

a)

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

b)

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

c)

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= \frac{1}{n_1-1}[∑X₁² - (( ∑X₁)²/n₁)]= \frac{1}{14} + [52829538 - (\frac{27588^{2} }{15}) = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

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3 years ago
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Answer:

Variance Σ i=1 (1 - Pi) /Pi^2

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Step-by-step explanation:

From the information given, we can get

E(T) = E(t1) + E(t2) ......... +E(tn)

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Answer:

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Step-by-step explanation: hoped I helped

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