2.40 divided by 6 is 0.40 so 0.40 times 10 is 4.00
First we need to look at the greatest and least points on each axis.
For x - the greatest is 2 and the least is -2 (that is the value of x for the points marked in the top left and right quadrants of the xy axis.
(Note that the points on the number line have a value for x of 1 & -1, but you need to look at highest value of points in all quadrants.)
For y - the greatest would be 3 and the least 0. Looking up and down the Y axis, you can see these intersections for the points given.
Now you need to find the D & R that is suitable for these values. We can only consider the first and last option because it correctly shows that the values for x & 7 must be between 2 & -2 and 0 and 3, The first one is incorrect because they have the D & R reversed. It is x that must be between 2 & -2 and y that must be between 0 & 3.
I hope you found this helpful.
10*9*8*7*6*5*4*3*2*1
Considering that when you use a digit you can't use it again, the possibilities of a number filling a specific position is one less than before because the number was already used.
Using this the answer should be
3,628,800
40 - 12 = 28
28 / 40 = 0.7
0.7 * 100 = 70%
The percentage decrease is 70%.
