The distance between the flagpole and the building is the number of feet between them
The building is 162 feet from the flagpole
<h3>How to determine the distance</h3>
The given parameters are:
- Flagpole = 40 feet
- Building Shadow = 324 feet
The flagpole's shadow is 50% longer than the flagpole.
So, the length (l) of the flagpole's shadow is:
The length of the building's shadow (d) is then calculated as:
Express as fraction
Solve for d
The distance (x) of the building from the flagpole is then calculated as:
Hence, the building is 162 feet from the flagpole
Read more about distance and bearing at:
brainly.com/question/11744248
Answer:
I believe the answer is 31.5
Step-by-step explanation:
210 = b(14)
210/14 = b
<span>15 square feet = b (base area)</span>
We have to determine, The tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each system of equations to its graph.
The groups of equation are as follows;
The y-intercept of equation = 1
The x-intercept of equation = -1/2
And The slope of equation = 2
Then,
At x = 0, y = 1
And at y = 0, x = -1/2
And at x = 2, y = 3
The first and second equation Corresponding with the third graph.
The y-intercept of equation = 0
The x-intercept of equation = 0
The slope of equation = 3
So at x = 0, y = 0 and at x = 2, y = 6
The equation Corresponds with the first graph
The y-intercept of equation = -2
The x-intercept of equation = 2
The slope of equation = 2
So at x = 0, y = -2 and at x = 2, y = 0
The equation Corresponds with the first graph.
The y-intercept of equation = 3
The x-intercept of equation = -2
The slope of equation = 2
So at x = 0, y = 3 and at x = -5, y = 0
The equation Corresponds with the fourth graph.
The y-intercept of equation = 2
The x-intercept of equation = -1/2
The slope of equation = 4
So at x = 0 y = 2 and at y = 0 x = -1/2 and at x = 0.5 y = 4
The equation Corresponding with the second graph.
Hey there!
Notice in the image, <em>I</em> is in between Q and C and QC is made up of QI and IC.
Knowing this, you can conclude that QI+IC=QC
Since you know that QI=3x-13 and IC=2x-12, you can add these two expressions together to get QC:
(3x-13)+(2x-12)
5x-25
Therefore, QC is 5x-25.
