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nikklg [1K]
3 years ago
9

HELP PLEASE >>>>>>>>>>>>>>>>>>>>>>

Mathematics
1 answer:
Damm [24]3 years ago
3 0

Answer:

A. \frac{2}{8}

B. \frac{6}{6}

C. \frac{8}{4}

Step-by-step explanation:

For A pick a fraction that is less than a whole number.

For B pick a fraction that is a whole number.

For C pick a fraction that is greater than a whole number.

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If b=5 what is b to the power of 5
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Step-by-step explanation:

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3 years ago
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A new operation is defined by a△b=a^2-b/b-a^2. 4△3.
dmitriy555 [2]

As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1

As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.

Given, a△b=a^2-b/b-a^2

now 4△3 = (4^2-3) / (3-4^2)  

4△3 = (16-3) / (3-16)        

4△3 = 13 / -13  

4△3 = -1

Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.

  • Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.

To learn more about mathematical operation, click on the link given below:

brainly.com/question/8959976

#SPJ1        

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