Plants employ photosynthesis to convert water, sunshine, and CO2 into oxygen and simple sugars that the plant may use as fuel. It is it important to add fertilizer to some soils because fundamental producers serve as the foundation of an ecosystem, fueling the subsequent trophic levels.
<h3>What is the photosynthesis process?</h3>
In the photosynthesis process, plants absorb carbon dioxide (CO2) and water (H2O) from the air and soil during photosynthesis. Water is oxidative within the plant cell, which means it loses electrons, but carbon dioxide is reductive, which means it receives electrons.
This converts water to oxygen and nitrogen to glucose. Photosynthesis is often used by plants to transform water, sunlight, and CO2 into oxygen and simple carbohydrates that the plant may utilize as fuel.
Therefore, Some soils require nutrients because basic producers contribute as the base of an ecosystem, feeding succeeding trophic levels.
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Answer:
Teller's break-even point in sales dollars for 2012 is $400,000
Explanation:
The formula to compute the break even point in dollars is shown below:
Break even point (in dollars) = (Fixed expenses) ÷ (contribution ratio)
where,
Fixed expense is $120,000
And, the contribution ratio equals to
= (Contribution per unit) ÷ (sales per unit) × 100
where,
Contribution is = Selling price - variable cost per unit
= $300 - $210
= $90 per unit
Now put the values to the above formula
So, the ratio would be
= ($90 per unit) ÷ ($300 per unit) × 100
= 30%
Now put the values to the above formula
So, the value would be
= $120,000 ÷ 30%
= $400,000
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
