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Paha777 [63]
3 years ago
6

Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer: 15.5^0C

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant =0.0821Latm/Kmol

T =temperature =  ?

T=\frac{PV}{nR}

T=\frac{0.987atm\times 12L}{0.0820 L atm/K mol\times 0.50mol}=288.5K=(288.5-273)^0C=15.5^0C

Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is 15.5^0C

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