The three particles of any atom are
<u>electron</u>) the smallest particle and is held in shells around the nucleus of the atom
<u>proton</u>) is found in the nucleus and is much larger than an electron
<u>neutron</u>) the same mass as a proton and also found in the nucleus of the atom
Answer:
0.0559 mol
Explanation:
Step 1: Given and required data
- Volume of air (V): 1.35 L
- Pressure of air (P): 750 torr
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Convert "P" to atm
We will use the conversion factor 1 atm = 760 torr.
750 torr × 1 atm/760 torr = 0.987 atm
Step 3: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 17.0 °C + 273.15 = 290.2 K
Step 4: Calculate the number of moles of air
If we assume air behaves as an ideal gas, we can calculate the moles (n) of air using the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 0.987 atm × 1.35 L/(0.0821 atm.L/mol.K) × 290.2 K = 0.0559 mol
Answer:
True
Explanation:
The oil drop experiment was carried out by Robert Millikan and Harvey Fletcher in 1909 to determine the charge of an electron. By balancing downward gravitation force with upward drag and electric force, they suspended small charged droplets of oil between two metal electrodes.
The charge over an oil droplet was often an integral value of e, was determined by changing the intensity of the electric field.
So, the given statement is true
Answer:
B. Pulmonary Circulation
Explanation:
Pulmonary circulation moves blood between the heart and the lungs. It transports deoxygenated blood to the lungs to absorb oxygen and release carbon dioxide. The oxygenated blood then flows back to the heart.
Answer:
1550.8
Explanation:
This is the ideal gas equation:
PV=nRT
We can rearrange the ideal gas equation to solve for the pressure of the nitrogen gas.
P=nRT/ V
We can find the pressure of the nitrogen gas by plugging in the values for the moles of gas, temperature, and volume. Since we want the pressure in units of Torr we use the R value62.36358L Torr K−1 mol-1
P=nRT/ V
(0.316 mol )(62.36358 L*Torr/K*mol)(315 K) / 4.00 L =1550 Torr
The correct answer is 1550
