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Westkost [7]
3 years ago
7

The last line of a proof represents

Mathematics
1 answer:
ki77a [65]3 years ago
7 0

Answer:

It represents the given information

Step-by-step explanation:

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Please help me with this problem​
weqwewe [10]

Answer:

<em>The measures of angles A, B, and C are respectively 21°, 125°, and 34°</em>

Step-by-step explanation:

<u>Equations</u>

We are given some conditions applying to the internal angles on a triangle ABC.

The measure of angle A is 13 less than the measure of angle C.

The measure of angle B is 11 less than 4 times the measure of angle C

Let x = measure of angle C

The first conditions states:

m\angle A = x-13

The second conditions states:

m\angle B = 4x-11

The sum of all angles must be 180°, thus:

x - 13 + 4x - 11 + x = 180

Simplifying:

6x -24 = 180

Adding 24:

6x = 204

Dividing by 6:

x = 204/6

x = 34

m\angle C = x = 34^\circ

m\angle B = 4x-11 = 4*34-11 = 125^\circ

m\angle A = x -  13 = 34 - 13 = 21^\circ

The measures of angles A, B, and C are respectively 21°, 125°, and 34°

6 0
2 years ago
Help please thank you
LuckyWell [14K]

Answer:

hmm i think its

1/2(x + y)

Step-by-step explanation:

because well... this would be eaiser for me if it said "of the" because "of the" is mostly used for multiply, but since it just said "the..." i can only guess. I think this may be the answer tho?

7 0
2 years ago
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Helppppppppppppp plssssssssss
alisha [4.7K]

Answer:

Step-by-step explanation:

8/12

5 0
2 years ago
Find the equation of a line given the point and slope below. Arrange your answer in the form y=mx+b, where b is the
erica [24]
C is the answer to the question
6 0
3 years ago
Dilate the trapezoid using center (-3,4) and scale factor 1/2.
pochemuha

The coordinates of the vertices of the image of the trapezoid are given as;

A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) , D'(x, y) = (- 7 / 2, 5 / 2).

<h3>How to find the image of a trapezoid by dilation?</h3>

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described :

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where O(x, y) - Center of dilation

k - Scale factor

And P(x, y) - Coordinates of the original point, P'(x, y) - Coordinates of the resulting point.

Since k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4),

Therefore, the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2)  (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B';

B'(x, y) = O(x, y) + k [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2)  (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C';

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2)  [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k  [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

To learn more on dilations:

brainly.com/question/13176891

#SPJ1

3 0
1 year ago
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