5x 2(x - 3) = -2(x

Phantasy [73]

I've searched online on what a graph look like in each given function and based on my online search, the given image of of the equation f(x) is a CUBIC FUNCTION.

A cubic function is like this: f(x) = ax³ + bx² + cx + d

The given graph can have this equation:

y = (x + 1) (x - 1) (x - 3)

5 0

3 years ago

Read 2 more answers

What is the LOWER QUARTILE OR Q1 of the data set: 24, 25, 29, 30, 31, 31. 32, 34, 34?*

MaRussiya [10]

Answer:

n=9

Step-by-step explanation:

Q1=n+1/4

=9+1/4

=10/4

=2.5

8 0

3 years ago

PLEASE HELP MEEEEEEEEEEEEEEEEEEEEEEEEEE!!! giving all the points I have

exis [7]

Answer:

Plug in and determine solution

Step-by-step explanation:#9-11 plug in the degrees C on the left side of the table into the equation and that should give you the degrees F, something like with #9; F = 9/5 (0) + 32.

#12-13, they have a relationship because Celsius can be converted to Farenheit and vise versa

3 0

3 years ago

6. A sector of a circle is a region bound by an arc and the two radii that share the arc's endpoints. Suppose you have a dartboa

Aliun [14]

Given the dartboard of diameter $20in$ , divided into 20 congruent sectors,

The central angle is $18^\circ$

The fraction of a circle taken up by one sector is $\frac{1}{20}$

The area of one sector is $15.7in^2$ to the nearest tenth

The area of a circle is given by the formula

$A=\pi r^2$

A sector of a circle is a fraction of a circle. The fraction is given by $\frac{\theta}{360^\circ}$ . Where $\theta$ is the angle subtended by the sector at the center of the circle.

The formula for computing the area of a sector, given the angle at the center is

$A_s=\dfrac{\theta}{360^\circ}\times \pi r^2$

<h3>Given information</h3>

We given a circle (the dartboard) with diameter of $20in$ , divided into 20 equal(or, congruent) sectors

<h3>Part I: Finding the central angle</h3>

To find the central angle, divide $360^\circ$ by the number of sectors. Let $\alpha$ denote the central angle, then

$\alpha=\dfrac{360^\circ}{20}\\\\\alpha=18^\circ$

<h3>Part II: Find the fraction of the circle that one sector takes</h3>

The fraction of the circle that one sector takes up is found by dividing the angle a sector takes up by $360^\circ$ . The angle has already been computed in Part I (the central angle, $\alpha$ ). The fraction is

$f=\dfrac{\alpha}{360^\circ}\\\\f=\dfrac{18^\circ}{360^\circ}=\dfrac{1}{20}$