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4 years ago

How many real solutions does each equation have? Enter "0", "1", or "2".

Mathematics

1 answer:

Marrrta [24]4 years ago

8 0

Answer:

1st=1 real # solution

2nd=1 real # solution

3rd=1 real number solution

Step-by-step explanation:

b^2-4ac=0 has 1 real number solution

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Suppose your local school district decides to randomly test high school students for attention deficit disorder (ADD). There are

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Answer:

Option C is correct. Option f is the same as option C

Step-by-step explanation:

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How do you distinguish between multiples and factors of a number, and justify your evaluation of the LCM & GCF of a set of n

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Answer:

Look to the explanation

Step-by-step explanation:

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For the function, evaluate the given expression. f(x, y) = 139 − x2 − y2. Find f(3, −9).

elena55 [62]

The value of the expression f(x,y)=139- $x^{2} -y^{2}$ at (3,-9) is 49.

Given that the expression is f(x,y)=139- $x^{2} -y^{2}$ and point (3,-9).

We are required to find the value of the expression f(x,y)=139- $x^{2} -y^{2}$ at (3,-9).

Expression is basically a combination of numbers, fractions, symbols, coefficients,determinants,indeterminants. They are mostly not found in equal to form.

Expression is f(x,y)=139- $x^{2} -y^{2}$ .

To find the value of expression f(x,y) at (3,-9).

f(3,-9)=139- $(3)^{2} -(9)^{2}$ (Squaring 3 and -9)

f(3,-9)=139-9-81 (Now add 9 and 81 and put minus sign before the result)

f(3,-9)=139-90

f(3,-9)=49 (Now subtract 90 from 139)

Hence the value of the expression f(x,y)=139- $x^{2} -y^{2}$ at (3,-9) is 49.

Learn more about expressions at brainly.com/question/723406

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