Question

Find the equation that going through these points.urgent!! will give the brainliest​

Answer 1

Answer:

The correct answer is y = -3x + 1.

Step-by-step Explanation:

First, you need to use the point slope formula to determine the slope. This is determined by the formula of the second y-coordinate (the y-coordinate in the second ordered pair) minus the first y-coordinate (the y-coordinate in the first ordered pair).

When subtracting the two values, you receive 7 - -5. You would use the KCC (keep, change, change) rule and keep positive 7, change the minus to addition, and turn negative 5 into positive 5. This gives you a value of 12.

Then, you use the same formula layout for the x-coordinates. Take the x-coordinate in the second ordered pair and subtract the x-coordinate in the first ordered pair to get -2 - 2 = -4.

Finally, to determine the slope, divide 12 and -4 to get -3.

Then, to get the y-intercept placed at the end, you will need to substitute the coordinate values from one of the ordered pairs into the equation y = -3x + b. I chose to use the first ordered pair, so:

-5 = -3(2) + b (Multiply the slope by x to earn the new value)

-5 = -6 + b (Add the -6 to the -5 to isolate the b)

1 = b (b = 1) (Learn that b = 1)

Your final equation will be y = -3x + 1.

Answer 2

Answer:

The equation is y = -3x + 1.

Step-by-step explanation:

First, you have to find the gradient of the equation using the formula :

$m = \frac{y2 - y1}{x2 - x1}$

Let (x1,y1) be (-2,7),

Let (x2,y2) be (2,-5),

$m = \frac{ - 5 - 7}{2 - ( - 2)}$

$m = \frac{ - 12}{4}$

$m = - 3$

Next, we have to use the slope-form equation y = mx + b where m is gradient and b is constant. So we have to find the value of c by substituing any coordinates into the equation :

$y = - 3x + b$

Let x = 2,

Let y = -5,

$- 5 = - 3(2) + b$

$- 5 = - 6 + b$

$b = 6 - 5$

$b = 1$