<h3>
Answer: 4</h3>
Start at 6 on the y axis. Draw an arrow so that it horizontally moves to the blue curve. Then draw an arrow straight down to vertically drop to x = 4
See the diagram below.
Follow this process in reverse to see that x = 4 leads straight up to the blue curve, and then to the left to land on y = 6. Keep in mind that the inverse reverses the input and output process, which is why I started with y instead of x.
Solve for <span>yy</span> in <span>2x+y=20<span>2x+y=20</span></span>How?
<span>y=20-2x<span>y=20−2x</span></span>
Substitute <span>y=20-2x<span>y=20−2x</span></span> into <span>-5y=-6x+12<span>−5y=−6x+12</span></span>How?
<span>-5(20-2x)=-6x+12<span>−5(20−2x)=−6x+12</span></span>
Solve for <span>xx</span> in <span>-5(20-2x)=-6x+12<span>−5(20−2x)=−6x+12</span></span>How?
<span>x=7<span>x=7</span></span>
Substitute <span>x=7<span>x=7</span></span> into <span>y=20-2x<span>y=20−2x</span></span>How?
<span>y=6<span>y=6</span></span>
Therefore,
<span>x=7<span>x=7</span></span>
<span>y=6<span>y=6</span></span>
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</span>
24x^3-40x^2. 45x-75
8x^2(3x-5). 15(3x-5)
(8x^2+15)(3x-5)
![\frac{1}{3} -3(\frac{2}{7}x-4) =\frac{1}{3} - \frac{6}{7}x +12](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20-3%28%5Cfrac%7B2%7D%7B7%7Dx-4%29%20%3D%5Cfrac%7B1%7D%7B3%7D%20-%20%5Cfrac%7B6%7D%7B7%7Dx%20%2B12)
![\frac{1}{3} -\frac{6}{7}x + \frac{36}{3} =\frac{37}{3}- \frac{6}{7}x = 12\frac{1}{3} -\frac{6}{7} x](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20-%5Cfrac%7B6%7D%7B7%7Dx%20%2B%20%5Cfrac%7B36%7D%7B3%7D%20%3D%5Cfrac%7B37%7D%7B3%7D-%20%5Cfrac%7B6%7D%7B7%7Dx%20%3D%2012%5Cfrac%7B1%7D%7B3%7D%20-%5Cfrac%7B6%7D%7B7%7D%20x)
A.) 1/3 - 3(2/7x) - (3)(4) No because - (3)(4) is -12
B.) 1/3 - 6/7x + 12 Yes
C.) -11 2/3 - 6/7x No because 37/3 is 12 1/3
D.) 12 1/3 - 6/7x Yes
E.) 1/3 - 6(1/7x - 2) = 1/3 - 6/7x + 12 Yes
F.) 1/3 + (-3)(2/7x) - (3)(4) No because - (3)(4) is -12
Your answer is B, D, and E
11:100
iwan:siobhan
if iwan gets 11% then iwan gets 89/100